Quantitative Ability Solutions ( Set 1 & Set 2 )

Solution to Quantitative Ability - Question Set 01 (10 Questions)

Q.01

6/9 + 6/t =1
6t+54/9t=1
6t+54=9t
t=18
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Q.02
((30/100)*40=12, (10/100)*12
=1.2
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Q.03
first 10 over score 32.... remaining 250 in 40 ovr so 6.25 run rate
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Q.04
7*2.5= 17.5 , 40*2.5= 100
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Q.05
B
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Q.06
99
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Q.07
60 mins = 54 km so in 50 min it will cover 45 km... so 10 min is right one
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Q.08
 a=9
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Q.09
1+5+10=16 ,480/16= 30,30*3=90
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Q.10
they are now 4 and 16 ......after 8 year they will be 12 and 24

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Solution to Quantitative Ability - Question Set 02 (10 Questions)

Q.01
the squer of hight * by the squer of base
In Figures 16 cm ^2
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Q.02
900-800=100/800*100=12.5%
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Q.03
787.5
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Q.04
r/w= 2/3 nd....w/b=4/5
now r=2w/3 ..... b=5w/4
r+w+b=70.........
now putting the values .... in r+w+b=70 we will get
2w/3+w+5w/4
then by lc of all these 
35w/12=70
.........................now w=840/35 nd white=24
now putting this value in equation b=5w/4 we can get the velue of blue ,,,,,,,b=5*24/4 = 30
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Q.05
30/0.5+10-7*2=126
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Q.06
 1000
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Q.07
39
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Q.08
12
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Q.09
33/100*33=10.89
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Q.10
1st suppose that r is 10 then 20% increase would be (r=12).. 1st find value with r (10) then with r(12) = 44 %
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